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，更多细节参见WPS官方版本下载
The original contract between the NHS and Crawford is publicly available, but has been heavily redacted
World Service,·23 Feb 2026,·26 mins
，详情可参考爱思助手下载最新版本
思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
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